Free Parabola calculator Calculate parabola foci, vertices, axis and directrix stepbystepGraph y=4(x2)^21 Find the properties of the given parabola Tap for more steps Use the vertex form, , to determine the values of , , and Since the value of is positive, the parabola opens up Opens Up Find the vertex Find , the distance from the vertex to the focus Tap for more stepsProfessionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge and
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Y=4 x^2 y=2-x x=-1 x=1
Y=4 x^2 y=2-x x=-1 x=1-Jul 22, 18Expression #=x^4y^4# Recall the factorization of the difference of two squares #a^2b^2 = (ab)(ab)# In our example, we will use this factorization twice Note #x^4 =(x^2)^2 and y^4 =(y^2)^2 # Applying the factorization above Expression #= (x^2y^2)(x^2y^2)# Now, the second factor above is also the difference of two squaresY4=2 (x1) Simple and best practice solution for y4=2 (x1) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it
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X 2 and x 2 y 2 <Answer to Find the area of the region bounded by y = (x 2)^2, \\ y=4 x^2, \\ x= 1, \\text{ and } x=4 By signing up, you'll get thousands of1 For every (x, y) in T, x y >
About x = 1Find the volume of the solid obtained by rotating theregion bounded by the given curves about the specified line Sketchthe reJul 02, 16Consider the small element width dx as shown, being revolved around the line x = 1 The cross sectional area (csa) of the washer of width dx is the csa of the outer circle minus the csa of the inner ie #dA = pi (1 x dx)^2 pi (1 x)^2# simplify the algebra with #u = 1 x# so we have #dA = pi ((udx)^2 u^2) = pi (2u dx dx^2)#The vertex for this parabola is \displaystyle{\left({1},{1}\right)} Explanation This is an equation for a parabola \displaystyle{y}={3}{\left({x}{1}\right)}^{{2
Free PreAlgebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators stepbystepConsider the following 1/x 1/y = 4 (a) Find y' by implicit differentiation y' = y^2/x^2 (b) Solve the equation explicitly for y and differentiate to get y' in terms of x y' = (c) Check that your solutions to part (a) and (b) are consistent by substituting the expression for y into your solution for part (a) y' =Answer to find the given limit lim ((x^21)(y^24))/((x1)(y2) (x,y)>(1,2)
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Solve x^2 y^2 = 1 for x;Knowledgebase, relied on by millions of students &Here y=2x/(1x^2) Make sense So multiply both side by (1x^2) a quadritic equation will form in which cofficent of x^2 will be y and that of x will be 2 And constant will be 2 For x to be real D greater than or equal to zero So D=2^2–4y^2≥0 now Y^
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6x 2y = 2 ;2 1 − 4 3 x 2 and with that y we can compue zY=x2 lets substitute one y for the other equation (doesnt matter which you use) x2=x1 solve x=x12 x=x1 xx
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8 Be careful in that our power series is now based at x 0 = 1 instead of x 0 = 0 xy00 y0 xy = x X1 n=2 n(n 1)a n(x 1)n 2 X1 n=1 na n(x 1)n 1 x X1 n=0 a n(x 1)n The problem is that we cannot incorporate x into a series with an (x 1) expansionSOLUTION 13 Begin with x 2 xy y 2 = 1 Differentiate both sides of the equation, getting D ( x 2 xy y 2) = D ( 1 ) , 2x ( xy' (1)y) 2 y y' = 0 , so that (Now solve for y' ) xy' 2 y y' = 2x y, (Factor out y' ) y' x 2y = 2 x y, and the first derivative asAnswer to Determine fx when f(x, y) = (x^2 y)(2y^2 x) 1 fx = 2y 2xy^2 3x^2 2 fx = y 4xy^2 3x^2 3 fx = 4xy^2 y 3x^2 4 fx =
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Tangent plane to (x^2 x y y^2) 1 at (x,y)=(1,2) SymmetricReduction((x^2 x y y^2) 1, {x^21, x}) (x^2 x y y^2) 1 >4x 2y = 28 * x=3 y=10 x=4 y=5 x=3 y=8 x=5 y=8 x 3y =12 ;Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor
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